A 50-kg lawn mower has its rear wheels driven. When starting from rest on a level surface, the rear wheels spin. The coefficient of kinetic friction is 0.50. The normal force on the rear wheels is 314 N and on the front wheels is 176 N. What is the forward acceleration of the mower?
Explanation
When driven wheels spin, the forward propulsion is provided by the force of kinetic friction. This force is calculated as the product of the coefficient of kinetic friction and the normal force on the driven wheels. The vehicle's acceleration is then found using ΣF = ma.
Other questions
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