In Example 4.9, a second-order circuit analysis, why is the initial voltage v(0+) equal to zero?
Explanation
Initial conditions are determined by the state of the circuit immediately before the switching event (at t=0-). In this example, the closed switch before t=0 places a short circuit directly across the capacitor, forcing its voltage to be zero. Due to the principle of capacitor voltage continuity, the voltage must also be zero immediately after the switch opens at t=0+.
Other questions
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