In the mathematical analysis of a simple transcriptional activator (protein A) binding to a promoter (pX), what is the relationship between the equilibrium constant (K), the association rate constant (kon), and the dissociation rate constant (koff)?

Correct answer: K equals kon divided by koff.

Explanation

The equilibrium constant (K), or association constant, for a binding reaction is a measure of the affinity between the two molecules. It is defined as the ratio of the 'on-rate' (kon) to the 'off-rate' (koff). A large K value indicates a strong interaction (high on-rate, low off-rate).

Other questions

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Question 9

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Question 13

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Question 16

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Question 17

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Question 19

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Question 23

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Question 25

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Question 26

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Question 31

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